If 3rd term of an hp is 7 and 7th terms of of hp is 3 then 10 th term is
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Answered by
5
a3= a+2d=79*1
a7= a+6d=3
by subtracting ep (1) from eq(2)
d= 1
putting i. ep 1 we get a=9
a10 = a +9d
9 +9*1
18 ans
a7= a+6d=3
by subtracting ep (1) from eq(2)
d= 1
putting i. ep 1 we get a=9
a10 = a +9d
9 +9*1
18 ans
Answered by
8
T3=1/a+2d=7. {2}-{1}= TU=1/a+6d=3
A+2d=1/7. {1}. 4d=4/21 ,d=1/21 a+6d=1/3. {2} a. Is also= 1/21 by this you can find the tenth term.
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