if 3sec^4A+8=10sec^2A,find the values of tanA.
Answers
Answered by
7
3sec⁴A + 8 = 10sec²A
3(sec²A)² + 8 = 10sec²A
Let sec²A = P
3P² + 8 = 10P
3P² - 10P + 8 = 0
3P² -6P - 4P + 8 = 0
3P(P -2) -4(P -2) = 0
(3P -4) (P -2) = 0
P = 4/3 and 2
sec²A = 4/3 and 2
[ we know,
sec²x - tan²x = 1 use, this ]
1 + tan²A = 4/3
tan²A = 4/3 -1 = 1/3
tan²A = ± 1/√3
again,
sec²A = 2
1 + tan²A = 2
tan²A = 1
tan²A = tan²π/4
tanA = ± 1
hence, tanA = ±1/√3 and ±1
3(sec²A)² + 8 = 10sec²A
Let sec²A = P
3P² + 8 = 10P
3P² - 10P + 8 = 0
3P² -6P - 4P + 8 = 0
3P(P -2) -4(P -2) = 0
(3P -4) (P -2) = 0
P = 4/3 and 2
sec²A = 4/3 and 2
[ we know,
sec²x - tan²x = 1 use, this ]
1 + tan²A = 4/3
tan²A = 4/3 -1 = 1/3
tan²A = ± 1/√3
again,
sec²A = 2
1 + tan²A = 2
tan²A = 1
tan²A = tan²π/4
tanA = ± 1
hence, tanA = ±1/√3 and ±1
Answered by
2
its answer is +1 and -1
pls Mark as brainlest
pls Mark as brainlest
Sinu7:
hahahaahaha.....
pls Mark as thank and brainlest
its only for u......
i know that after getting brainliest u will forget but i like your style for that u are brainliest....
thanks
no i nevrr forgot
no i nevrr forgot
Similar questions