Math, asked by HelpingHaley, 1 year ago

If 3secA-2cosB=3^(1/2) and B is 30, find A

Answers

Answered by saicharan06467
1
2*cosB=3^1/2
so,
3secA=2*3^1/2
secA=2/3^1/2
A=30
Answered by mysticd
2
3secA-2cosB = √3

3secA- 2*cos 30=√3

3secA - 2*√3/2=√3

3secA -√3 =√3
3secA = 2√3
sec A = 2√3/3
secA =2/√3

secA =sec 30
A=30

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