If 3secA-2cosB=3^(1/2) and B is 30, find A
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Answered by
1
2*cosB=3^1/2
so,
3secA=2*3^1/2
secA=2/3^1/2
A=30
so,
3secA=2*3^1/2
secA=2/3^1/2
A=30
Answered by
2
3secA-2cosB = √3
3secA- 2*cos 30=√3
3secA - 2*√3/2=√3
3secA -√3 =√3
3secA = 2√3
sec A = 2√3/3
secA =2/√3
secA =sec 30
A=30
3secA- 2*cos 30=√3
3secA - 2*√3/2=√3
3secA -√3 =√3
3secA = 2√3
sec A = 2√3/3
secA =2/√3
secA =sec 30
A=30
mysticd:
Ur welcome
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