Question

if 3seca - 5 = 0 then cot a = ___​

Answer 1

Answer:

Step-by-step explanation:

We are given that 3sec \theta - 5=03secθ−5=0

3sec \theta - 5=0

3sec \theta=5

sec \theta=\frac{5}{3}

We know that sec\theta = \frac{Hypotenuse}{Base}

On comparing

Hypotenuse = 5

Base = 3

To find perpendicular we will use Pythagoras theorem:

Hypotenuse^2=Perpendicular^2+Base^2Hypotenuse

2

=Perpendicular

2

+Base

2

\begin{gathered}5^2=Perpendicular^2+3^2\\5^2-3^2=Perpendicular^2\\\sqrt{5^2-3^2}=Perpendicular\\4=Perpendicular\end{gathered}

5

2

=Perpendicular

2

+3

2

5

2

−3

2

=Perpendicular

2

5

2

−3

2

=Perpendicular

4=Perpendicular

\begin{gathered}Cot\theta = \frac{Base}{Perpendicular}\\Cot\theta = \frac{3}{4}\end{gathered}

Cotθ=

Perpendicular

Base

Cotθ=

4

3

Step-by-step explanation:

I hope it's helpful