Question

If 3sin+4cos =5 then find the value of 4sin-3cos

Answer 1

Step-by-step explanation:

3sin + 4cos =5

Let 4sin-3cos =x

Squarring on both sides on both the equations we will get

9sin^2 +16cos^2 +24sin×cos=25

16sin^2 +9cos^2 - 24sin×cos=x^2

Now adding both equations we will get

25(cos^2 + sin^2)=25+x^2

25=25+x^2

Then we will get x=0