Math, asked by anushka2947, 6 months ago

If 3sin + 5cos =5 prove that 3sin + 5cos = 3​

Answers

Answered by Anonymous
5

Answer:

Given,

Step-by-step explanation:

3sin + 5cos = 3

squaring both side of the equation

( 3sin + 5cos )^2 = 5^2

= 9sin^2 + 25 cos^2 + 30sin25cos = 25

= 9( 1 - cos^2) + 25( 1 - sin^2) + 30sincos = 25

= 9 - 9cos^2 + 25 - 25sin^2 + 30sincos = 25

= 9 = cos^2 + 25sin^2 + 30sincos

= 9 = 25sin^2 - 30sincos + 9cos^2

= 3^2 = 5^2sin^2 - 30sincos + 3^2cos

= 3^2 = (5sin)^2 - 30sincos + (3cos)^2

= 3^2 = ( 5 sin - 3cos)^2

=(5sin - 3cos)^2 = 3^2

square will be cut out

= 5sin - 30cos = -+3

Answered by criskristabel
5

HEY POTATO!❤

HOPE THIS HELPS!

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