If 3sin + 5cos =5 prove that 3sin + 5cos = 3
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Answer:
Given,
Step-by-step explanation:
3sin + 5cos = 3
squaring both side of the equation
( 3sin + 5cos )^2 = 5^2
= 9sin^2 + 25 cos^2 + 30sin25cos = 25
= 9( 1 - cos^2) + 25( 1 - sin^2) + 30sincos = 25
= 9 - 9cos^2 + 25 - 25sin^2 + 30sincos = 25
= 9 = cos^2 + 25sin^2 + 30sincos
= 9 = 25sin^2 - 30sincos + 9cos^2
= 3^2 = 5^2sin^2 - 30sincos + 3^2cos
= 3^2 = (5sin)^2 - 30sincos + (3cos)^2
= 3^2 = ( 5 sin - 3cos)^2
=(5sin - 3cos)^2 = 3^2
square will be cut out
= 5sin - 30cos = -+3
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