If 3sinθ + 5cosθ=5, then find the value of 5sinθ-3cosθ.
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Given,
3 sinθ + 5 cosθ = 5
Now, squaring both sides, we get
(3 sinθ + 5 cosθ)² = 5²
➽ 9 sin²θ + 30 sinθ cosθ + 25 cos²θ = 25
➽ 9 (1 - cos²θ) + 30 sinθ cosθ + 25 (1 - sin²θ) = 25
➽ 9 - 9 cos²θ + 30 sinθ cosθ + 25 - 25 sin²θ = 25
➽ 25 sin²θ - 30 sinθ cosθ + 9 cos²θ = 9
➽ (5 sinθ - 3 cosθ)² = 3²
➽ 5 sinθ - 3 cosθ = 3,
which is the required answer.
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Anonymous:
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