Question

If 3sin A=18, then the value of cosec A is

A) 18/3
B) 3/18
C) 18/18
D) 38/3​

Answer 1

Answer:

3sinA = 18

So

sinA = 18/3

cosecA = 1/sinA

cosecA = 3/18

but sir , there is problem in question

In your question

the sin ratio is a proper fraction

while usually sin ratio is in improper fraction

Because the opposite side is on numerator while hypotenuse is on denominator

and hypotenuse being the longest side of triangle

should always convey that

in any ratio , in which hypotenuse is in denominator with respect to any side in triangle should be a improper fraction

but no problem it's all right

Step-by-step explanation:

hope it helps

pls mark as brainliest

Answer 2

Answer:

Option (B)$\frac{3}{18}$ is the required value of Cosec A

Step-by-step explanation:

Explanation:

Given , 3sinA = 18

As we know that the relation between  sin x and cosec x is

sinx = $\frac{1}{cosec x}$

Step 1:

we have 3 sinA = 18

⇒ sinA = $\frac{18}{3}$

And we know that sin x = $\frac{P}{h}$  and cosec x = $\frac{h}{p}$

Where p is perpendicular and h is hypotenuse

So , p is equal to 18 and h is equal to 3 .

Cosec A = $\frac{h}{p}$       ..........(i)

Now put the value of p and h in the above equation we get ,

Cosec A = $\frac{3}{18}$

Final answer :

Hence , the value of  Cosec A  is  $\frac{3}{18}$

#SPJ2