Question

If 3sin alpha=5sin beta then tan alpha +beta/2/tan alpha - beta/2 is

Answer 1

Answer:

54

Step-by-step explanation:

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Answer 2

Answer:

$\\ given \: that \: 3 \sin( \alpha ) = 5 \sin( \beta ) \\ therefore \: \sin( \alpha ) \div \sin( \beta ) = 5 \div 3 \: \\ then \: by \: componedo \: and \: dividendo \: \\ \sin( \alpha ) + \sin( \beta ) \div \sin( \alpha ) - \sin( \beta ) = 8 \div 2 \\ then \: 2 \sin( \alpha + \beta \div 2) \cos( \alpha - \beta \div 2) \div 2 \cos( \alpha + \beta \div 2) \sin( \alpha - \beta \div 2) = 4 \\ \: hence \: \tan( \alpha + \beta \div 2) \div \tan( \alpha - \beta \div 2) = 4$