Question

if 3sin theta - 4cos theta is 0 then what is the value of 3sin theta + 4 cos theta is how much​

Answer 1

Step-by-step explanation:

ANSWER

3sin θ+4cosθ = 5

Squaring both sides

9sin 2 θ+16cos 2 θ+24sinθcosθ=25

9(1 cos 2 =θ)+16(1−sinθ)+24sinθcosθ=25

9−9cos

2 θ+16−16sin

2 θ+24sinθcosθ=25- 9 cos

2 θ−16sin 2 θ+24sinθcosθ=25916

9 cos 2 θ+16sin 2

θ−24sinθcosθ=0

(3cosθ4sinθ) 2 =0

3cosθ−4sinθ=0

Alternate Method:

If ax+by=m and ax−by=n

then (a 2 +b 2 )(x 2 +y 2 )=m

2 +n 2

Here

a=sinθ

x = 3, m = 5, and b = cos θ y = 4, n = ?

(sin 2 θ+cos 2 θ)(9+16)(5) 2 +n 2

n 2 = 0, n = 0

3sinθ−4cosθ = 0

Answer 2

Step-by-step explanation:

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