Question

If 3Sin2 - 4Sin + 1 = 0 then find possible values of Sin​

Answer 1

$sin = 1 \: \: and \: \: \frac{1}{3}$

Step-by-step explanation:

$Given, \: \: \: 3sin^{2} - 4sin + 1 = 0 \\ 3 {sin}^{2} - 3sin - sin + 1 = 0 \\ 3sin(sin - 1) - 1(sin - 1) = 0 \\ (3sin - 1)(sin - 1) = 0 \\ 3sin - 1 = 0 \: \: \: and \: \: \: \: sin - 1= 0 \\ 3sin = 1 \: \: \: and \: \: \: sin = 1 \\ sin = \frac{1}{ 3} \: \: \: and \: \: \: sin = 1$