Question

If 3sinA = 4 prove that sin^2A + cos^2A =1

Answer 1

hey.....!! here is ur answer.......(ur question is Missprint)
_____________________________
Given that,
3tanA = 4
tanA = 3/4= P/B , where P= 3 and B= 4
_____________________________
According to the Pythagoras theoram
we know that,
(H)²= (P)²+(B)²
H²= (3)²+(4)²
H² = 9+16
H² = 25
H = 5
then we know that,
sinA = P/H = 3/5 and
cosA = B/H= 4/5
then we have to prove that,
sin²A + cos²A = 1
on taking L.H.S
sin²A + cos²A
(3/5)² + (4/5)²
9/25 + 16/25
= 1 = R.H.S
HENCE PROVED.........
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I hope it helps u.............☺️☺️☺️
THANK YOU...............✌️✌️✌️✌️

Answer 2

(Yourr question is Missprint) it should be tan a not sin a_____________________________Given that,3tanA = 4tanA = 3/4= P/B , where Perpendicular= 3 and Base =  4_____________________________According to the Pythagoras theoramwe know that,(H)²= (P)²+(B)²    H is for hypotenuseH²= (3)²+(4)²H² = 9+16H² = 25H = √25 = 5


Then we also know that,sinA = P/H = 3/5 and  cosA = B/H= 4/5

To prove that,   - sin²A + cos²A = 1

On taking L.H.S,

sin²A + cos²A(3/5)² + (4/5)²9/25 + 16/25= 1 = R.H.S 


HENCE PROVED..........

THANK U ★ ★ ★
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