Question

If 3sinA + 4cosA = 5 prove that tanA + secA = 2​

Answer 1

Answer:

hi

your answer is here !

Step-by-step explanation:

3sinA + 4cosA = 5

or, (3/5)sinA + (4/5)cosA =1

or, (3/5)sinA + (4/5)cosA =(sinA)^2 + (cos)^2

{bcz, (sinA)^2 + (cosA)^2 = 1}

or, (3/5) sinA + (4/5) cosA =

sinA.sinaA + cosA.casA

this implies that:

sinA=3/5 and cosA =4/5

hence,

tanA = sinA/cosA

=(3/5) / (4/5)

=(3/5) × ( 5/4)

= 3/4

I hope this will help you...

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