Question

If 3sinA + 4cosA = 5 then find tanA

Answer 1

3sinA + 4cosA = 5
or, (3/5)sinA + (4/5)cosA =1
or, (3/5)sinA + (4/5)cosA =(sinA)^2 + (cos)^2
{bcz, (sinA)^2 + (cosA)^2 = 1}
or, (3/5) sinA + (4/5) cosA =
sinA.sinaA + cosA.casA
this implies that:
sinA=3/5 and cosA =4/5

hence,
tanA = sinA/cosA
=(3/5) / (4/5)
=(3/5) × ( 5/4)
= 3/4

I hope this will help you...