Math, asked by vvsts1728, 9 months ago

.) If 3sinA -COSA =0 and 0°<A<90°,find the value of A.

Answers

Answered by gogirigajendra

1

Step-by-step explanation:

3sinA-CosA=0

3sinA=CosA
3=cosA/sinA where cos@/sin@= cot @
A=cot-1 3

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