Question

IF 3SINX + 4COSX = 5 ; 4COSX - 3SINX = ?

Answer 1

(3sinx+4cosx)=5

(3sinx+4cosx)²=25

9sin²x+16cos²x+24sinx.cosx=25

9(1-cos²x)+16(1-sin²x)+24sinx.cosx=25

9-9cos²x+16-16sin²x+24sinx.cosx=25

-9cos²x-16sin²x+24sinx.cosx+25=25

9cos²x+16sin²x-24sinx.cosx=0

(3cosx)²+(4sinx)²-2(3cosx)(4sinx)=0

(3cosx-4sinx)²=0

3cosx-4sinx=0

Answer 2

Answer:

4CosX - 3 SinX = 0

Step-by-step explanation:

3sinx + 4cosx = 5

9(1-cos²x) + 16(1-sin²x) + 24*sinx*cosx = 25

9-9cos²x +16 -16sin²x + 24*sinx*cosx = 25

9cos²x + 16sin²x + 2*(3cosx)*(4sinx) = 0

(3cosx)² + (4sinx)² - 2*(3cosx)*(4sinx) = 0

(4sinx - 3cosx)² = 0

4sinx - 3cosx = 0

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