If 3t times the 4th term of an AP is equal to 9times its 10the term,then show that's 23is zero.
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Answered by
5
Answer:
Step-by-step explanation:
3*a4=9*a10
3(a+3d)=9(a+9d)
3a+9d=9a+81d
-6a=72d
a=-12d
Answered by
3
Answer:
Given,
If 3 times the 4th term of an A.P is equal to 9 times its 10th term.
So,
3 × a(4) = 9 × a(10)
=> 3 ( a + 3d ) = 9 ( a + 9d )
=> 3a + 9d = 9a + 81d
=> 3a - 9a = 81d - 9d
=> -6a = 72d
=> a = -12d....(1)
Now,
a(23) = a + 22d
-12d + 22d [ From (1) ]
= 10d
•°•a(23) is not equal to zero
Step-by-step explanation:
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