Question

if 3tan A=√3.find the sin3A and cos2A​

Answer 1

Step-by-step explanation:

TanA = 1/√3

A= 30°

sin90° = 1

cos60° = 1/2

Answer 2

Given that : 3tanA = √3

=> tanA = 1/√3

=> A = 30° ( As we know that : tan30° = 1/√3 )

Now, sin3A = 3sinA-4sin³A

=> 3sin30°-4sin³30°

=> 3×1/2 - 4(1/2)³ = 3/2-1/2

=> 1

And cos2A = 1-2sin²A = 1-2sin²30°

=> 1-2(1/2)²

=> 1-1/2 = 1/2

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