If 3tan A=4 evaluate sinA +cosA /sinA-cosA
Answers
Answered by
2
SinA+CosA/SinA-CosA
Dividing numerator and denominator by CosA
=[( SinA/CosA)+1]/[(SinA/CosA)-1]
=( tanA+1)/(tanA-1)
= [(4/3)+1]/[(4/3)-1]
= (7/3)/(1/3)
= 7
Dividing numerator and denominator by CosA
=[( SinA/CosA)+1]/[(SinA/CosA)-1]
=( tanA+1)/(tanA-1)
= [(4/3)+1]/[(4/3)-1]
= (7/3)/(1/3)
= 7
himanshusingh52:
Hii
Answered by
2
I hope it will help you
Attachments:
Similar questions