Question

if 3tan A=4,then find cosA​

Answer 1

Step-by-step explanation:

3Tan A=4

or tanA=4/3

as we know that tanA=perpendicular/base

therefore by pythagorean

H^2=B^2+P^2

H^2=3^2+4^2

H=

$\sqrt{9 + 12}$

H=

$\sqrt{21}$

As cosA=base/hypotenuse

=

$3 \div \sqrt{21}$