Question

if 3tan A=4,then find sinA and cosA?​

Answer 1

Given -

3tan A = 4

tanA = 4/3 = p/b

then,

we need to find hypotenuse.

• h² = p² + b²

• h² = (4)² + (3)²

• h² = 16 + 9

• h = √25

h = 5

Then,

Sin A = p/h

• Sin A = 4/5

CosA = b/h

• CosA = 3/5

here is your answer....