If 3tan A - 5 cos B = root3 and B= 90degree, find the value of A.
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given B=90degrees
3tanA-5cosB=√3
3tan A-5cos90=√3
3tanA-5×0=√3
3tan A=√3
tan A=√3/3
tan A=1/√3
tan 30=1/√3
therefore, A=30degrees
3tanA-5cosB=√3
3tan A-5cos90=√3
3tanA-5×0=√3
3tan A=√3
tan A=√3/3
tan A=1/√3
tan 30=1/√3
therefore, A=30degrees
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