Question

if 3tan theeta = √3,then find the value of acute angle 'theeta'​

Answer 1

this is your answer
hope u will understand

Answer 2

$3 \tan( \alpha ) = \sqrt{3 }$

$\tan( \alpha ) = \frac{ \sqrt{3} }{3}$

$\tan( \alpha ) = \frac{1}{ \sqrt{3} }$

$\tan( \alpha ) = \frac{\pi}{6}$

$\alpha = \frac{\pi}{6}$