if 3tan theta=1 find sin theta and cot theta
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Answered by
4
3 Tan ¢ = 1
Tan¢ = 1/3 = P / B
P = 1 , B = 3 , H = ?
We know that,
H² = P² + B²
H² = 1² + 3²
H² = 1 + 9
H² = 10
H = √10 .
Therefore,
Sin ¢ = P / H = 1 / √10
And,
Cot ¢ = B/P = 3/1 = 3.
Tan¢ = 1/3 = P / B
P = 1 , B = 3 , H = ?
We know that,
H² = P² + B²
H² = 1² + 3²
H² = 1 + 9
H² = 10
H = √10 .
Therefore,
Sin ¢ = P / H = 1 / √10
And,
Cot ¢ = B/P = 3/1 = 3.
Answered by
2
tan Q= 1/3
in ∆abc
ac2=ab2+bc2
ac2=3*3+1*1
ac2=9+1
ac2=10
ac=√10
sinQ =1/√3
cosQ=3/√3
in ∆abc
ac2=ab2+bc2
ac2=3*3+1*1
ac2=9+1
ac2=10
ac=√10
sinQ =1/√3
cosQ=3/√3
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