Question

If✓3tan°=1,then find the value of sin2°-cos2°

Answer 1

√3tan°=1
or tan°=1/√3
or p/b=1/√3
.•. p=1,b=√3
so that , h=√p^2+b^2
.•.h=2
.•.sin°=p/h and cos°=b/h
so,sin°=1/2 and cos°=√3/2

therefore, sin^2°-cos^2°
=(1/2)^2+-(√3/2)^2
=1/4-3/4
=-1/2 answer

another method:-.
√3tan°=1
or tan°=1/√3
or tan°=tan 30°
so, °=30°

therefore,
sin^2°-cos^2°
=sin^2 30°-cos^2 30°
=(1/2)^2-(√3/2)^2
=1/4-3/4
= -1/2 answer

hope this will help you.

Answer 2

Put it in the calculator like it is and you'll get= -0.9644913303