Question

if √3tanA-1=0 find sinA,cotA,secA and sin2A+cos2A

Answer 1

Hi ,

It is given that ,

√3 tanA - 1 = 0

tanA = 1/√3

tanA = tan 30°

Therefore ,

A = 30° ---( 1 )

i ) sinA = sin 30° = 1/2

ii ) cotA = 1/tanA = 1/( 1/√3 ) = √3

iii ) secA=1/cosA=1/cos 30°= 1/( √3/2 )= 2/√3

iv ) sin 2A + cos 2A

= sin( 2 × 30° ) + cos ( 2 × 30° )

= sin 60° + cos 60°

= √3/2 + 1/2

= ( √3 + 1 )/2

I hope this helps you.

: )