if 3tanA=4
find
5sinA-3cosA/5sinA+2cosA
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Answered by
2
Answer:
11/26
Step-by-step explanation:
divide the identity by cosA
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Answered by
1
Answer:
3tanA=4
tanA=4/3
tanA=opposite/adjacent
BC=4k
AB=3k
AB²+BC²=AC²
(3k)²+(4k)²=AC²
AC²=9k²+16k²
AC=√25k²
AC=5k
5sinA-3cosA/5sinA+2cosA
5*4/5-3*3/5/5*4/5+2*3/5
4-9/5/4+6/5
20-9 /20+6
-------. --------
5. 5
11/26
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