Question

If 3tanA=4
Find the value of 4cosA - sinA /2cosA - sinA . Class 10th ch 8...​

Answer 1

Step-by-step explanation:

$3tanA=4 = > tanA=(4 \div 3) = ( \sinA \div \cosA) \\ = > cosA = 3 \div ( \sqrt{ {3}^{2} + {4}^{2} } \\ = > cosA = 3 \div 5 \\ and \: \\ sinA = 4 \div ( \sqrt{ {3}^{2} + {4}^{2} } = 4 \div 5$

$((4cosA - sinA) /(2cosA - sinA)) \\ = ((4 \times (3 \div 5) - (4 \div 5)) \div (2 \times( 3 \div 5) - (4 \div 5)))$

$= (8 \div 5) \div (2 \div 5) = 8 \div 2 = 4$

ANS.