Question

if 3tanA=4, proof that

1 - sin a upon 1 + cos A is equal to 1 upon 2 root 2 ​

Answer 1

Answer:

3tanA=4

or, tanA=4/3=p/b

Using Pythagorus theorem, h²=p²+b² we get,

h²=4²+3²

or, h²=16+9

or, h²=25

or, h=5 (neglecting the negative sign)

∴, sinA=b/h=4/5 and cosA=h/p=3/5

√(1-sinA/1+cosA)

=√(1-4/5)/(1+3/5)

=√{(5-4)/5}/{(5+3)/5}

=√(1/5)/(8/5)

=√1/5×5/8

=√1/8

=1/2√2

Answer 2

Answer:

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hope it's helpful....

:-)