Question

if 3tanA=4,then the value of 2sinA-7cosA by 3cosA+4​

Answer 1

Answer:

3tanA = 4

tanA = 4/3

As tan = Opposite side/Adjacent side ,

Consider a right triangle with following measurements.

Opposite side = 4

Adjacent side = 3

Hypotenuse(By Pythagoras Theorem) = 5

sinA = Opposite/Hyptenuse = 4/5

cosA = Adjacent/Hypotenuse = 3/5

(2sinA - 7cosA)/(3cosA + 4)

= (2(4/5) - 7(3/5))/(3(3/5) + 4)

= ((8-21)/5) ÷ ((9 + 20)/5)

= (-13/5) ÷ (29/5)

= (-13/5)(5/29)

= -13/29