Question

If 3tanO = 4, find the value of 4cosO-sinO/ 2cosO+sinO

Answer 1

Answer:

3tanθ=4

tanθ=

3

4

2cosθ+sinθ

4cosθ−sinθ

=

2cosθ+sinθ

4cosθ−sinθ

×

cosθ

cosθ

----------( Multiply and divide by cosθ )

=

cosθ

2cosθ+sinθ

cosθ

4cosθ−sinθ

=

2+

cosθ

sinθ

4−

cosθ

sinθ

=

2+tanθ

4−tanθ

=

2+

3

4

4−

3

4

=

6+4

12−4

=

10

8

=

5

4