If 3tanO = 4, find the value of 5sin0- 3cos0/5sinO+2cosO
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Answered by
5
Step-by-step explanation:
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Answered by
8
Answer:
11/26
Step-by-step explanation:
3tanΘ=4,
hence tan Θ=4/3
in 5sinΘ-3cosΘ/5sinΘ+2cosΘ divide numerator and denominator both by cosΘ
that gives us,
5tanΘ-3/5tanΘ+2
we have value of tan Θ =4/3
hence putting values we get,
5x4/3-3 / 5x4/3+2
20/3 - 3 / 20/3 +2
20-9/3 / 20+6/3
11/3 / 26/3
the denominator are same hence we can cancel them.
∴ we get,
11/26 as our answer.
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