If 3tanO=4,show that(3sinO+2 cosO/3sin O-2cosO
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1
Answer:
Correct option is
D
2
Given, 2−cos
2
θ=3sinθcosθ
Dividing both sides by cos
2
θ, we get
2sec
2
θ−1=3tanθ
2(1+tan
2
θ)−1=3tanθ
⇒2+2tan
2
θ−1=3tanθ⇒2tan
2
θ−3tanθ+1=0
⇒2tan
2
θ−2tanθ−tanθ+1=0
⇒2tanθ(tanθ−1)−(tanθ−1)=0
⇒(2tanθ−1)(tanθ−1)=0
⇒tanθ=
2
1
and 1
⇒cotθ=2 and 1
Step-by-step explanation:
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