If |Ā|=3units ,|B|= 4units and|Ā×B|=6units,then the angle between ĀandB is
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Explanation:
|A×B|=|A| |B| sin thetha
given that
|A| =3units,|B|= 4units
|A×B|= 6units
6 = 3×4 sin thetha
6 = 12 sin thetha
6/12= sin thetha
1/2 = sinthetha
sin30°= sinthetha
therefore,
the angle between the vectors A and B= 30°
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