Question

If(3x+1)^3+(x-3)^3+(2x-4)^3=6(3x+1)(x-3)(x-2) then x is

Answer 1

Answer:

x = 1

Step-by-step explanation:

Given--->

( 3x+1 )³ + ( x-3 )³+ ( 2x-4 )³=6 (3x+1) ( x - 3 ) ( x - 2 )

To find---> Find the value of x .

Solution---> We have an identity if

a + b + c = 0 , then

a³ + b³ + c³ = 3abc

ATQ,

(3x + 1)³ + (x - 3 )³ + (2x - 4 )³= 6 (3x + 1) (x - 3) (x - 2)

(3x + 1)³+(x - 3)³+(2x - 4)³= 3 × 2 (3x+1) (x-3) (x-2)

(3x + 1)³+(x - 3)³+(2x - 4)³= 3 (3x+1) (x-3) (2x - 4)

Let, a = ( 3x + 1 ) , b = ( x - 3 ) , c = ( 2x - 4 ) , putting these values in it , we get

=> a³ + b³ + c³ = 3 a b c

Applying above identity , we get ,

It means , a + b + c = 0

Putting values of a , b and c i.e. , a = 3x + 1 ,

b = x - 3 and c = 2x - 4 , we get,

=> 3x + 1 + x - 3 + 2x - 4 = 0

=> 6x - 6 = 0

=> 6x = 6

=> x = 6 / 6

=> x = 1

#Answerwithquality&BAL

Answer 2

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$\huge\underline{\underline{\texttt{\purple{x=1}}}}$

#answerwithquality #bal