Question

If (3x+1)(3x-1)=(9x2-p) then the value of p is​

Answer 1

Answer:

1

Step-by-step explanation:

Given that,

(3x+1)(3x-1) = (9x^2-p)

To find the value of p.

We know that,

• (a+b)(a-b) = (a^2-b^2)

Here, we have,

• a = 3x
• b = 1

Therefore, we will get,

=> (3x)^2 - (1)^2 = (9x^2 -p)

=> 9x^2 - 1 = 9x^2 - p

=> p = 1

Hence, required value of p is 1.

Some identities:-

• (a+b)^2 = a^2 + 2ab + b^2
• (a-b)^2 = a^2 - 2ab + b^2

Answer 2

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❍Question :-

⋄ If (3x+1)(3x-1)=(9x²-p) then find the value of p?

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Solution :-

(3x+1)(3x-1)=(9x²-p)

By using this identity

(a-b) (a+b)=(a²-b²)

(9x² -1)=(9x²-p)

-1 =-p

p=1

∴ The value of p is 1.

⋄Some other identities⋄

☛(a + b)²= a²+ 2ab + b²

☛ a² – b²= (a + b)(a – b)

☛(x + a)(x + b) = x²+ (a + b) x + ab.