Question

If 3x+1/3x=3
Find 27x^3+1/27x^3

Answer 1

Answer:

$27x {}^{3} + \frac{1}{27x {}^{3} } = 27 - \frac{1}{x} - 9x$

Step-by-step explanation:

Given,

$3x + \frac{1}{3x} = 3 \\ cubing \: both \: the \: sides \: \\ (3x + \frac{1}{3x} ) {}^{3} = 3 {}^{3} \\ by \: using \: identity \: (a + b) {}^{3} = a {}^{3} + b {}^{3} + 3ab(a + b) \\ = (3x) {}^{3} + ( \frac{1}{3x} ) {}^{3} + 3(3x)( \frac{1}{3x})(3x + \frac{1}{3x} ) = 27 \\ = 27x {}^{3} + \frac{1}{27x {}^{3} } + 9x + \frac{1}{x} = 27 \\ = 27x {}^{3} + \frac{1}{27x {}^{3} } = 27 - \frac{1}{x} - 9x$

Hope this will help you!!

Answer 2

Answer:

27x^3+1/27x^3 =-2

Step-by-step explanation:

Given,

• 3x+ 1/3x = 3
• 3(x+1/x)=3
• x+ 1/x = 3/3
• x+ 1/x = 1

Now,

27x^3 + 1/27x^3

= (3x)^3 + (1/3x)^3

= (x + 1/x)^3 - 3x.1/x (x + 1/x)

{applying , x^3 + 1/x^3 formula}

= (1)^3 - 3(1)

=1-3

=-2

Mark Branliest if you are helped anyhow by the answer.