If(3x-1)^4=a4x^4+a3x^3+a2x^2+a1x+a0, then find other the value of a4+3a3+9a2+27a1+81a0.
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Answer:
the value of _ a4+3.a3+9.a2+27.a1+81.a0 is 44
Step-by-step explanation:
Given
(3x-1)⁴ = a4.x⁴+a3x³+a2x²+a1x+a0 ......eq1
L. H S
(3x-1)⁴ = 81x⁴- 108x³+ 54x²- 12x + 1
compare with eq1
- a4 = 81
- a3 = -108
- a2 = 54
- a1 = -12
- a0 = 1
put these values in >> a4+3.a3+9.a2+27.a1+81.a0
= 81+3.(-108)+8.(54)+27.(-12)+81.1
= 81 - 324 + 432 - 324 + 81
= 44
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