If "3x-(1)/(4y)=24",then the value of "8x(6x-(1)/(y))+(1)/(12y^(2))(4-3y+36xy^(2))" ,where "y!=0," is:
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The value is 8x(7x-(1)/(y))+(1) (12y^(2)) (4-3y+36xy^((2))’’,where ‘’y!=0
Step-by-step explanation:that it’s different numbers
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