If 3x - 1/4y = 6, then find the value of 4x - 1/ 3y ?
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3x–1/4y = 6
x = (6+1/4y)/3 = 2+1/12y
4x–1/3y = 4(2+1/12y)–1/3y = 8 + 1/3y – 1/3y = 8
x = (6+1/4y)/3 = 2+1/12y
4x–1/3y = 4(2+1/12y)–1/3y = 8 + 1/3y – 1/3y = 8
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