if 3x+1/5y =2 find (5x+1/3y)³
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0
Answer:
I don't know the exact but it may be some kind of,
On putting
x
1
=X and
y
1
=Y in given equations, we get
3
X
+
5
Y
=
15
1
⇒5X+3Y=1 ...(i)
2
X
+
3
Y
=
12
1
⇒6X+4Y=1 ...(ii)
On multiplying (i) by 6 and (ii) by 5, we get
30X+18Y=6
−
3
0X
−
+
20Y=
−
5
−2Y=1
∴Y=−
2
1
On putting Y=−
2
1
in (i), we get
5X+3×−
2
1
=1⇒5X=
2
5
⇒X=
2
1
∴x=
X
1
=2,y=
Y
1
=−2
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