Question

If (3x-1)^7=a_7x^7+a_6x^6+...+a_1x+a_0 then a_7+a_6+...+a_1+a_0=​

Answer 1

Answer:

We have,

Step-by-step explanation:

Put x=1 in

(3x-1)^7 = a7x^7+a6x^6+...+a1x+a0

you will get

2^7= a7+a6+a5+..+

so answer is 2^7=128

 

 Answer =128