if (3x+1) is factor of (3x^2+bx+2) then what is the value of b
Answers
Answered by
6
Answer:
b=7
Step-by-step explanation:
f(x) =3x^2+bx+2
g(x) =3x+1
=-1/3
f(-1/3)=3×(-1/3)^2+b×(-1/3)+2
=3×(1/9)-b/3+2
=1/3-b/3+2
=(1-b+6)/3
=(7-b)/3
=>(7-b)/3=0
=>7-b=0
=>-b=-7
=>b=7
Hope it's help u!!!!
Answered by
0
answer: b=7
explanation:
3x+1=0
x=-1/3
by factor theorem,
3(-1/3)^2+b(-1/3)+2=0
3(1/9)-b/3+2=0
1/3-b/3+2=0
-b/3=-1/3-2
-b/3=-7/3
therefore, b=7
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