If (3x-15°)and (x+ 5°) are complementary angles then find the angles
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According to the question ,
(3x-15°) + (x+5°) = 90°
3x+x+5°-15° = 90°
4x-10°=90°
4x=100°
x=25°
So , First Angle = 3x-15° = 3*25°-15° =75°-15°=60°
Second Angle =x+5°=25°+5°=30°
So , Angles are 60° and 30°
(3x-15°) + (x+5°) = 90°
3x+x+5°-15° = 90°
4x-10°=90°
4x=100°
x=25°
So , First Angle = 3x-15° = 3*25°-15° =75°-15°=60°
Second Angle =x+5°=25°+5°=30°
So , Angles are 60° and 30°
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