If 3x+18° and 2x+25° are supplementary, find the value of x.
Answers
Answered by
12
3x + 18 + 2x + 25 = 180
5x + 43 = 180
5x = 180 - 43
5x = 137
x = 137/5
x = 27.4
5x + 43 = 180
5x = 180 - 43
5x = 137
x = 137/5
x = 27.4
Answered by
10
Hi ,
Let a and b are two supplementary
angles
a = 3x + 18°
b = 2x + 25°
a + b = 180°
3x + 18 + 2x + 25 = 180°
5x + 43 = 180
5x = 180 - 43
5 x = 137
x = 137/5
x = 27.4°
I hope this helps you.
: )
Let a and b are two supplementary
angles
a = 3x + 18°
b = 2x + 25°
a + b = 180°
3x + 18 + 2x + 25 = 180°
5x + 43 = 180
5x = 180 - 43
5 x = 137
x = 137/5
x = 27.4°
I hope this helps you.
: )
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