Question

if 3x^2+13+4=(ax+b)(cx+d), then find the value of ac+bd

Answer 1

Answer:

20

Step-by-step explanation:

rhs

(ax+b) (cx+d) = acx^2+adx+bcx+bd

comparing gives

ac= 3, bd=13+4= 17

ac+bd= 3+17= 20