if 3x^2-2k+m=0 find k where x=2 and m=3
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Answered by
2
3(2^2) -2k +3 = 0
(3*4) + 3 = 2k
12 + 3 = 2k
15 = 2k
15/2 = k
i hope this will help you
-by ABHAY
(3*4) + 3 = 2k
12 + 3 = 2k
15 = 2k
15/2 = k
i hope this will help you
-by ABHAY
Answered by
0
3x²-2k+m=0
or 3*(2)² -2k+3=0
or 12-2k+3=0
or 15-2k=0
or -2k = -15
or k = 15/2
or 3*(2)² -2k+3=0
or 12-2k+3=0
or 15-2k=0
or -2k = -15
or k = 15/2
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