Question

If √3x^2-4x+34+√3x^2-4x-11=9, then value of
(√3x^2-4x+34-√3x^2-4x-11) is​

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Answer 1

Answer:

Step-by-step explanation:

Let  a = sqrt(3x^2 -4x + 34) and b = sqrt(3x^2 - 4x -11 ).

Now, (1) is            a+b  =  9

         (2) is           a^2 - b^2 = 45  i.e  (a-b)(a+b) = 45

 Dividing (2) by (1)  gives (a-b) = 45/9 = 5    i.e   (3)