If (3x+2)-(5y-3) and (6x+3)+(2y+4) are congugates find x and y
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Let 3y+4x=1
----- equation (1)
and y−x=5 ----- equation (2)
Multiplying equation (2) with 4 we
get, 4y−4x=20 ----- equation (3)
Adding equations (1) and (3), we get 7y=21=>y=3
Substituting y=3 in the equation (2), we get 3−x=5=>x=−2
Hence, x=−2;y=3
Since the lines are concurrent, x=−2;y=3 should satisfy the equation 5y+bx=3
=>5(3)+b(−2)=3
=15−2b=3
2b=12
=>x&y=6
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