Question

If 3X^2+ax+4 is perfectly divisible by x-5 then a is

Answer 1

Here is your answer

If x-5 is perfectly divisible then x-5=0
x = 5.

put it above equation
$3(5) {}^{2} + a(5) + 4 = 0 \\ 75 + 5a + 4 = 0 \\ 5a = - 79 \\ a = - 79 \div 5 \\ a = - 15.8$
Hope it helps you

Answer 2

hi here your answer
X-5=0
X=5
put the value of X in give equation
3(5)(5)+a(5)+4=0
75+5a+4=0
79+5a=0
5a=-79
a=-79/5